http://www.geeksforgeeks.org/archives/8405

^ Similar Question.

On Mar 25, 4:49 pm, atul anand <[email protected]> wrote:
> wont work for all cases...ignore
> i will post the algo....once i fix it
> On 25 Mar 2012 17:06, "Amol Sharma" <[email protected]> wrote:
>
>
>
>
>
>
>
> > @atul : it would be better for all to understand if you write the algo
> > instead of writing the code..
> > --
>
> > Amol Sharma
> > Third Year Student
> > Computer Science and Engineering
> > MNNIT Allahabad
> >  <http://gplus.to/amolsharma99> 
> > <http://twitter.com/amolsharma99><http://in.linkedin.com/pub/amol-sharma/21/79b/507><http://www.simplyamol.blogspot.com/>
>
> > On Sun, Mar 25, 2012 at 4:51 PM, atul anand <[email protected]>wrote:
>
> >> @shady : yes i guess this is what question says:-
> >> so acc to this below algo work , i didnt execute it but i guess it will
> >> work
>
> >> void nextSmaller(int arr[],int n)
> >> {
> >> s1 s;
> >> int i,next,ele;
>
> >> s.top=-1;
> >> push(&s,0);
>
> >> for(i=1;i<n;i++)
> >> {
> >> next=arr[i];
> >>  if(isEmpty(&s))
> >> {
> >>       ele=pop(&s);
> >>       while(arr[ele] > next)
> >>       {
> >>  swap(arr,ele,i);
> >>                   next=arr[ele];
> >> if(isEmpty(&s)==0)
> >> {
> >> break;
> >>  }
> >>   ele=pop(&s);
> >>       }
> >>       if(ele > next)
> >>       {
> >> push(&s,ele);
> >>       }
>
> >> }
>
> >> push(&s,i);
> >>  }
>
> >> }
>
> >> On Sun, Mar 25, 2012 at 4:36 PM, shady <[email protected]> wrote:
>
> >>> @gene
> >>> i think for  3 4 2 you need to start from left most element, and then
> >>> make substitutions one by one.
> >>> so it will be
> >>> 3 4 2
> >>> 2 4 3
> >>> 2 3 4
>
> >>> @all i googled a bit, and found that O(n) solution is possible for it,
> >>> any idea ?
>
> >>> On Sun, Mar 25, 2012 at 1:59 PM, Kartik Sachan 
> >>> <[email protected]>wrote:
>
> >>>> +1 @saurabh...:P
>
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