This is a subset sum problem. You have to find a subset of elements of array whose sum is x/2, where x is sum of all the elements of the array.
On Sat, May 19, 2012 at 2:07 PM, payal gupta <[email protected]> wrote: > this wont work out as we need to partition the elements to get the average > of the two parts to be equal and not the sum of the two parts.. > > > On Fri, May 18, 2012 at 11:57 PM, Ramindar Singh <[email protected]>wrote: > >> Not sure if i am correct but still be very close. >> >> 1. Intial Array is A with n elements >> 2. Sort the Array's in descending order >> 3. take 2 more arrays B and C in which u keep the partition >> 4. pull the one element from A to B and keep keep track of the sum's in >> both the arrays B & C >> 5. Try to reach the sum in B by pulling the elements from A >> 6. Continue till all the n elements are partitioned. >> 7. If in the end still some difference is there b/w B and C, it can be >> settled by exchanging the elements among them as they both would be sorted. >> >> hope this helps... >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To view this discussion on the web visit >> https://groups.google.com/d/msg/algogeeks/-/BRRM2sjulSEJ. >> >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
