soln pls

Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652


On Sun, May 20, 2012 at 5:49 PM, jalaj jaiswal <[email protected]>wrote:

> I can give you a dynamic programming approach in O(n^2) and O(n) space .
>
> On Tue, May 15, 2012 at 12:22 PM, Ashish Goel <[email protected]> wrote:
>
>>
>> I am unclear about the answer provided by Programming Pearls on the 
>> question. What this does is to find longest string whose beginning is 
>> separated by exactly M chars.
>>
>> The original question is to find the longest string duplicated M times. Any 
>> ideas on the approach for this? I could think of having a suffix tree with 
>> each node keeping a count to keep track of "while insertion how many times 
>> this node was passed while going down"
>>
>> #include <stdlib.h>
>> #include <string.h>
>> #include <stdio.h>
>>
>> int pstrcmp(char **p, char **q)
>> {   return strcmp(*p, *q); }
>>
>> int comlen(char *p, char *q)
>> {    int i = 0;
>>      while (*p && (*p++ == *q++))
>>              i++;
>>      return i;
>> }
>>
>> #define M 1
>> #define MAXN 5000000
>> char c[MAXN], *a[MAXN];
>>
>> int main()
>> {   int i, ch, n = 0, maxi, maxlen = -1;
>>     while ((ch = getchar()) != EOF) {
>>         a[n] = &c[n];
>>         c[n++] = ch;
>>     }
>>     c[n] = 0;
>>     qsort(a, n, sizeof(char *), pstrcmp);
>>     for (i = 0; i < n-M; i++)
>>         if (comlen(a[i], a[i+M]) > maxlen) {
>>             maxlen = comlen(a[i], a[i+M]);
>>             maxi = i;
>>         }
>>     printf("%.*s\n", maxlen, a[maxi]);
>>     return 0;
>> }
>>
>> Best Regards
>> Ashish Goel
>> "Think positive and find fuel in failure"
>> +919985813081
>> +919966006652
>>
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>
>
>
> --
> Regards,
>
> Jalaj Jaiswal
> Software Developer,
>  Adobe Systems
> +91-9019947895
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