@Guneesh But 0<=N , K<=1000 so N^N could be have 1000 digits. There is no direct upper bound on N, but there is an upper bound on K (i.e. K <= 1000). And we need to check N^N == K, so N^N cant be more than 1000.
On Monday, June 11, 2012 1:56:13 PM UTC+5:30, Guneesh wrote: > > @abhisheikh read the problem statement again...it says 1000 digits not > 1000 value.. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/dswHt9ucfDEJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
