given a matrix m*n print elements in spiral
eg
1 2
3 4
5 6 => 1,2,4,6,5,3
1
2
3 =>1,2,3
i wrote following code but for the case 2 printing 1,2,3,2
I wish to avoid keeping a counter of how many elements have been print so
far...
void spiral(int a[], int m, int n) {
while ( (rs<(m+1)/2) && (cs <(n+1)/2)) {
int r=rs;
int c=cs;
for (int j=c;j<n-c-1;j++) printf("%d ",a[r][j]);
for (int i=r;i<m-r-1;i++) printf("%d ",a[i][n-c-1]);
for (int j=n-c-1;j>c;j--) printf("%d ",a[m-r-1][j]);
for (int i=m-r-1;i>r;i--) printf("%d ",a[i][c]);;
rs++;cs++;
}
}
Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652
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