At first look it appears to be  a simple problem of discrete binary search.
Take sum of b[i] as the upper_bound and 0 as the lower bound. Then apply a
simple binary search for the number of pages that can be given to a
student. Complexity : O(N log( sum( B ) ) )


On Thu, Jun 14, 2012 at 12:26 PM, algogeek <[email protected]>wrote:

> In a library there are N books with the number of pages in i th book given
> by bi . These books are to be distributed among K  students such that the
> difference between the largest sum of pages in the books assigned to any
> student and the smallest sum of number of pages in the books assigned to
> any student is minimum for the given input. Also the books are arranged in
> a certain order and this order must never be changed.
> For eg:
> suppose B[ ] contains the number of pages in each book.
> then
> N=6
> K=3
> B={3,7,8,2,6,4}
>
> then the output will be 0 as we can give book 1 and 2 to student 1 and
> book 3 and 4 to student 2 and the remaining to student 3. That makes 10
> pages for student 1 10 for 2 and 10 for 3 and thus the difference is 0
>
> similarly if B={3,6,8,2,6,4} then the minimum difference will be 1 .
>
>
>
>
>
>
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-- 
Hemesh singh

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