@anmol  my algo will work even if nos are not in ascending
order .correct me if i am wrong.

On Jun 15, 7:45 am, Amol Sharma <[email protected]> wrote:
> sry ignore the last comment for i wanted to say -
> your algo will work only when the numbers given are consecutive.
>
> --
>
> Amol Sharma
> Final Year Student
> Computer Science and Engineering
> MNNIT Allahabad
>
> <http://gplus.to/amolsharma99>
> <http://twitter.com/amolsharma99><http://in.linkedin.com/pub/amol-sharma/21/79b/507><http://www.simplyamol.blogspot.com/><http://facebook.com/amolsharma99>
>
>
>
>
>
>
>
> On Fri, Jun 15, 2012 at 8:06 PM, Amol Sharma <[email protected]> wrote:
> > @enchantress :
> > your algo will work only when the number given are positive.
> > --
>
> > Amol Sharma
> > Final Year Student
> > Computer Science and Engineering
> > MNNIT Allahabad
> >  <http://gplus.to/amolsharma99> 
> > <http://twitter.com/amolsharma99><http://in.linkedin.com/pub/amol-sharma/21/79b/507><http://www.simplyamol.blogspot.com/>
>
> > On Fri, Jun 15, 2012 at 7:01 PM, shiv narayan 
> > <[email protected]>wrote:
>
> >> this is the running code to find no of triangles using brute force
> >> technique
> >> logic: in a triangle having sides a,b,c; then a+b>c(if c is greatest side)
> >> correct me if i am wrong.
>
> >>  #include<iostream>
> >> #include<conio.h>
> >> using namespace std;
> >> int max(int a,int b,int c)
> >> {
> >>     return ((a>b?a:b)>c?(a>b?a:b):c);
> >> }
> >> int main()
> >> {
> >> int n,a[120],t,p,q;
> >> cin>>t;
> >> while(t--)
> >> {
> >> cin>>n;
> >> for(int i=0;i<n;i++)
> >> cin>>a[i];
> >> int i,j,no_of_triangles=0,sum=0,largest_edge;
> >> for(i=0;i<n-2;i++)
> >> {
> >> for(j=i+2;j<n;j++)
> >> {
> >> sum=a[i]+a[i+1]+a[j];
> >> largest_edge=max(a[i],a[i+1],a[j]);
> >> if(sum-largest_edge>largest_edge)
> >> {
> >> no_of_triangles++;
> >> cout<<a[i]<<" "<<a[i+1]<<" "<<a[j]<<"\n";}
>
> >> }
> >> }
> >> cout<<no_of_triangles<<endl;
> >> }
> >> getch();
> >> return 0;
> >> }
>
> >> On Wednesday, 13 June 2012 22:18:01 UTC+5:30, payel roy wrote:
>
> >>> Let's say there are N sides are given. Length of them are like
> >>> 1,2,3,4,5,....N.
>
> >>> How do you determine how many tri-angles can be made out of these N
> >>> sides?
>
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