Prem Krishna Chettri +1
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The precedence of && > ||
&& has higher priority than || .
check in this case:
int i=0,j=0,k=0;
int x =i++ || ++j && k;
the output is : x=0 i=1 j=1 k=0
the control flows from L to R . First 'i' is incremented( but i=0 is
checked as it's post increment, but in o/p i=1), since || finds 0 (ie i=0 )
at its left, the control flows further to the right and evaluates ++j. Now
++j&&k is equivalent to 1&&0, which makes it 0, (notice && is evaluated
first). now 0 || 0 is evaluated, which comes out to be 0, so x is assigned
0 as the total expression evaluates as false.
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On Sun, Jun 17, 2012 at 11:26 PM, rahul venkat <[email protected]>wrote:
> yea it s short circuiting ....
>
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Firoz Khursheed
Computer Science & Engineering
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