http://www.spoj.pl/problems/FAVDICE/

On Sun, Jun 17, 2012 at 8:43 PM, Doom <[email protected]> wrote:

> If we expand it.. E(t) = E(t1) + E(t2) + E(t3) + ... + E(tn);
> here I am able to derive E(t1) as N/1 using the expression E(t1) = 1/N +
> ((N-1)/N)(E(t1) + 1);
> but how do I proceed?
> How do I derive the E(t2) and so on??
>
> What do these values mean??
> Does it mean like E(t2) is the no. of expected throws to get value 2??
>
> Any help on this?
>
> On Sunday, 17 June 2012 00:09:13 UTC+5:30, amitesh wrote:
>>
>> This problem is similar to Coupan collector problem.
>> http://en.wikipedia.org/wiki/**Coupon_collector%27s_problem<http://en.wikipedia.org/wiki/Coupon_collector%27s_problem>
>>
>> In your case the answer is
>>
>> [image: For N-Dice ; \newline \sum_{i=1}^{N} N/i \newline for\; N =~2 ;
>> \newline \sum_{i=1}^{2} 2/i = 2/1 + 2/2 = 3 \newline]
>>
>>
>> Hope it helps!
>>
>>
>> --
>> Amitesh
>>
>>
>>
>>
>> On Sat, Jun 16, 2012 at 5:18 PM, Gaurav Popli <[email protected]>wrote:
>>
>>> What is the expected number of throws of his die while it has N sides
>>> so that each number is rolled at least once?
>>> e.g
>>> for n=2 ans 3.00
>>>     n=12 ans is 37.24...
>>> i refrd to expectation tutuorial at
>>> http://www.codechef.com/wiki/**tutorial-expectation<http://www.codechef.com/wiki/tutorial-expectation>but
>>>  still couldnt
>>> get the logic...
>>>
>>> any help?
>>>
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