find the element nearest to zero.make it pivot element.then apply one pass
of quicksort over the array.this is O(n)
On Thu, Jun 21, 2012 at 12:27 AM, Akshat Sapra <[email protected]>wrote:
> void make_group( int a[], int size) {
> int j = 0;
>
> for ( int i = 0; i < size; i++ ) {
> if ( a[i] < 0 ) {
> swap(a[i],a[j]);
> j++;
> }
> }
> }
>
>
> --
>
>
> Akshat Sapra
> Under Graduation(B.Tech)
> IIIT-Allahabad(Amethi Campus)
> *--------------------------------------*
> [email protected]
> [email protected]
> rit20009008@ <[email protected]>iiita.ac.in
>
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--
Abhishek Sharma
Under-Graduate Student,
PEC University of Technology
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