Krishna,
  how can you store a address pointing to k bits value into k/2 bits? XOR
is the way to do this.


-- 
Amitesh




On Thu, Jun 21, 2012 at 1:20 AM, Krishna Kishore
<[email protected]>wrote:

> *np *is nothing but *next_pointer. np[x] *does mean *x->np *which is the
> next pointer to node. Actually I am thinking in this way about *np, *that
> it stores the *XOR* value of *next* and *prev* pointers.Or Since *np *is
> a k-bit integer, the first k/2 bits wil be used for *next*, and other k/2
> bits wil be used for *prev *pointer.
>
> On Wednesday, 20 June 2012 18:28:07 UTC+5:30, adarsh kumar wrote:
>>
>> Simple!
>> Just traverse the doubly linked list and keep track of next and previous
>> of each node, and do XOR and save the result in a new pointer, what
>> according to you is "np".
>> Be careful about boundary cases, i.e head and tail, though.
>>
>> On Wed, Jun 20, 2012 at 5:16 PM, Krishna Kishore <
>> [email protected]> wrote:
>>
>>> Explain how to implement doubly linked lists using only one pointer value
>>> * np[x*] per item instead of the usual two (next and prev). Assume that
>>> all pointer values can be interpreted as
>>> k-bit integers, and define* np[x] to be np[x] = next[x] XOR prev[x],*the 
>>> k-bit “exclusive-or” of next[x] and prev[x]. (The value NIL is
>>> represented by 0.) Be sure to describe what information is needed to
>>> access the head of the list. Show how to implement the SEARCH, INSERT, and
>>> DELETE operations on such a list. Also show how to reverse such a list in
>>> O(1) time.
>>>
>>> This is the Question in the Book "*Introduction To Algorithms" *By
>>> CORMEN ( MIT Press ) Page Number : 209 , Problem No: 10.2-8.
>>>
>>> Thanks in Advance.
>>>
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