@adarsh kumar

are u sure it's worst case will be O (log n) ??
i think iff array is fully sorted O(n) will be required to say "NO
such element present"

On Sat, Jun 23, 2012 at 1:11 PM, adarsh kumar <[email protected]> wrote:
> This is a variation of binary search, the difference being that we have to
> search for an element that is greater than its immediate left one and lesser
> than its immediate right one. Just implement binary search with these
> additional constraints, thereby giving O(log n).
> In case of any difficulty/error, let me know.
>
> On Sun, Jun 24, 2012 at 1:27 AM, Hassan Monfared <[email protected]>
> wrote:
>>
>> Given an array of integers find a peak element of array in log(n) time.
>> for example if A={3,4,6,5,10} then peak element is 6  ( 6>5 & 6>4 ).
>>
>> Regards.
>>
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