On Wednesday, 25 July 2012 20:59:47 UTC+5:30, jatin wrote:
>
> For the first o/p even though i save it like u have done then too it's
> showing me an empty string .....
> for 2nd as Vindya has stated it should give me error but my compiler is
> showing me 30 as it's output(the ans shd be 25 if not error) ?
>
ahh..ther's sumthng wrong with my compiler .. wen am running it online it's
givng me the correct answ.
> On Wednesday, 25 July 2012 20:42:56 UTC+5:30, deepikaanand wrote:
>
>> for the first o/p qs
>> as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
>> save the base address and den let p2 move forward with p1
>>
>> char *p1="Name";
>> char *p2;
>> p2=(char *)malloc(20);
>> char *save;
>> save = (char *)malloc(20);
>> save = p2;
>> if(p2==NULL)
>> cout<<"\n NOT ENOUGH SPACE";
>> else
>> {
>>
>> while(*p2++=*p1++);
>>
>> printf("%s\n",save);
>> }
>>
>> for the second qs o/p = 25
>> cz post incr means first use den incr thererfore 5*5
>>
>>>
> On Wednesday, 25 July 2012 20:42:56 UTC+5:30, deepikaanand wrote:
>>
>> for the first o/p qs
>> as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
>> save the base address and den let p2 move forward with p1
>>
>> char *p1="Name";
>> char *p2;
>> p2=(char *)malloc(20);
>> char *save;
>> save = (char *)malloc(20);
>> save = p2;
>> if(p2==NULL)
>> cout<<"\n NOT ENOUGH SPACE";
>> else
>> {
>>
>> while(*p2++=*p1++);
>>
>> printf("%s\n",save);
>> }
>>
>> for the second qs o/p = 25
>> cz post incr means first use den incr thererfore 5*5
>>
>>>
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