@vaibhav : yes it will be a balanced BST.

On Wed, Aug 8, 2012 at 11:29 AM, vaibhav shukla <[email protected]>wrote:

> @Navin
>
> By your algo of starting with the middle node,I guess a balanced BST would
> be created. Is it ?
>
>
> On Wed, Aug 8, 2012 at 1:24 AM, Navin Kumar <[email protected]>wrote:
>
>> 1. Convert your Binary tree into doubly linked list.
>> 2. Sort the linked list using merge sort
>> 3. Build BST using doubly linked list by each time selecting middle node
>> and recursively calling left part of linked list and right part of linked
>> list.
>>
>> On Tue, Aug 7, 2012 at 10:23 PM, vaibhav shukla 
>> <[email protected]>wrote:
>>
>>> Hi all
>>>
>>> The problem is to convert a binary tree into Binary Search Tree
>>>
>>> My approach was :
>>>
>>> 1. Store the Inorder traversal of BT in an array.
>>> 2. Sort the array in ascending order.
>>> 3. Again do inorder traversal and write the Node's  data from array one
>>> by one.
>>>
>>> This approach takes O(n) extra space.
>>> Can someone tell a better approach that doesn't require any extra space.
>>> Thanx.
>>>
>>> --
>>> best wishes!!
>>>  Vaibhav
>>>
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>
>
>
> --
> best wishes!!
>  Vaibhav
>
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