you can do it easily by counting the number that can be formed with 1 digit
= 26, then 2 digit = 26*26... similarly find the length of the answer and
then can find the number by searching using bsearch over the number of
different characters.

if someone can do it with base % method,, then it is great :-P


On Thu, Aug 16, 2012 at 11:19 PM, Wei.QI <[email protected]> wrote:

> @yq, didn't I ask you this question before?
>
> On Fri, Aug 10, 2012 at 4:48 PM, yq Zhang <[email protected]> wrote:
> > @shiv, your code is correct go compute the base 26 number. However, this
> > question is not base 26 number obviously.
> >
> >
> >
> > On Wed, Aug 8, 2012 at 4:46 AM, shiv narayan <[email protected]>
> > wrote:
> >>
> >> this is similar to conversion of no in base 26.( where digits are
> >> a,b,c,d...z) just think it like decimal to binary conversion here base
> is
> >> instead 26.
> >>
> >> char Carr[26]={a,b,c...z}
> >> i=0;
> >> int arr[];
> >> do
> >> {
> >> arrr[i++]=n%26;
> >> n/=2;
> >> }
> >> while(n) ;
> >> for(int i=n-1;i>=0;i--)
> >> cout<<Carr[a[i]];
> >>
> >> correct me if i am wrong.
> >> On Wednesday, 8 August 2012 12:56:56 UTC+5:30, ashgoel wrote:
> >>>
> >>> Imagine a sequence like this: a, b, c...z, aa, ab, ac...zz, aaa, aab,
> >>> aac.... aax, aaz, aba, abc... (Its same as excel column names). Given
> an
> >>> integer (n), generate n-th string from the above sequence.
> >>>
> >>>
> >>> Best Regards
> >>> Ashish Goel
> >>> "Think positive and find fuel in failure"
> >>> +919985813081
> >>> +919966006652
> >>
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