since the function fn() is returning "bool"(here "true " which is of one
byte ) value whose size is 1 byte in C
so your output is showing 1 .
if you change the return type of your function ..say "int " it will print 4
byte (size of integer on your machine ).or say double it will print 8 byte
(size of double on your machine )
On Fri, Aug 31, 2012 at 9:25 PM, Rahul Kumar Patle <
patlerahulku...@gmail.com> wrote:
> #include<stdio.h>
> #include<stdbool.h>
>
> bool fn(char *a , int b , char c)
> {
> return true;
> }
>
> int main()
> {
> int it = 2;
> char ct = 'c';
> char a[30];
> printf("%d\n",(sizeof(fn(a , it , ct))));
> }
>
> in gcc 32 bit compiler the above code is always printing 1 even if i
> change the no of argument in fn()
> why?? pls explain..
>
>
>
> --
> Thanks and Regards:
> Rahul Kumar
> Patle<http://www.linkedin.com/profile/view?id=106245716&trk=tab_pro>
> M.Tech, School of Information Technology
> Indian Institute of Technology, Kharagpur-721302,
> India<http://www.iitkgp.ac.in/>
> Mobile No: +91-8798049298, +91-9424738542
> Alternate Email: rahulkumarpa...@hotmail.com
>
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--
*RAHUL KUMAR DUBEY*
*BTech-3rd year *
*Computer Science &Engineering *
*Motilal Nehru National Institute Of Technology*
*Allahabad[211004],UP.*
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