my prev code was incorrect :-
here is the correct code :-
void combination(char str[3][100],int len,int row,int j)
{
static char prn[3];
int i=0,k=0,p=0;
if(j==2)
{
prn[j]='\0';
printf("\n%s",prn);
return;
}
for(p=row;p<len;p++)
{
for(k=0;k<strlen(str[p]);k++)
{
prn[j]=str[p][k];
combination(str,len,p+1,j+1);
}
}
}
call : combination(str,len,0,0); // len = number of words
for input : str[3][100]={"hello","how","a"};
output :-
hh
ho
hw
ha
eh
eo
ew
ea
lh
lo
lw
la
lh
lo
lw
la
oh
oo
ow
oa
ha
oa
wa
On 10/1/12, ~*~VICKY~*~ <venkat.jun...@gmail.com> wrote:
> Hi atul,
>
> Thanks for your response. I found your idea matches very much with my
> approach which i claimed buggy. The problem in my code is that It prints
> some extra strings in the end. For eg for the below input it prints
> 24(5*3+3*3) comb instead of 15(5*3). I couldn't recognize how to resolve
> it. Could any1 help me out.
>
> #include<iostream>
> #include<string>
> #include<cstdio>
>
> string str[]={"hello", "how","a"};
>
> void print_all(string sel, int k,int n)
> {
> if(k == n){
> static int count =1;
> cout<<"---->"<<count++<<" "<<sel<<endl;
> return;
> }
> for(int i = k; i < n ; i++)
> {
> for(int j = 0; j < str[i].length(); j++)
> {
> print_all(sel+str[i][j], k+1,n);
> }
> }
> }
> int main()
> {
> print_all("",0,2);
> }
> //code ends
>
> On Mon, Oct 1, 2012 at 12:33 AM, atul anand <atul.87fri...@gmail.com>
> wrote:
>
>> void combination(char str[2][100],int len,int row,int j)
>> {
>> static char prn[3];
>> int i=0,k=0,p=0;
>>
>> if(j==2)
>> {
>> prn[j]='\0';
>> printf("\n%s",prn);
>> }
>> for(p=row;p<len;p++)
>> {
>> for(k=0;k<strlen(str[row]);k++)
>> {
>> prn[j]=str[row][k];
>> combination(str,len,p+1,j+1);
>>
>> }
>> }
>> }
>>
>> call : combination(str,len,0,0);// len = number of words in your eg call
>> will be
>> combination(str,2,0,0);
>>
>> On 9/30/12, ~*~VICKY~*~ <venkat.jun...@gmail.com> wrote:
>> > Given 'n' arrays each of variable sizes. Write code to print all
>> > combinations. Each combination contains one element from one array
>> > each.
>> > For eg:
>> > string str[]={"hello", "how"}
>> >
>> > op will be
>> > hh
>> > ho
>> > hw
>> > eh
>> > eo
>> > ew
>> > lh
>> > lo
>> > lw
>> > lh
>> > lo
>> > lw
>> > oh
>> > oo
>> > ow
>> >
>> > 15 sets would come, includes repetition.
>> >
>> > My approach had bugs and didn't work. Help would be appreciated.
>> >
>> >
>> >
>> >
>> > --
>> > Cheers,
>> >
>> > Vicky
>> >
>> > --
>> > You received this message because you are subscribed to the Google
>> > Groups
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>> >
>> >
>>
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>>
>
>
> --
> Cheers,
>
> Vicky
>
> --
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