@atul: keep one more checking outside loop for element at 0 th index.
Because when n = 0  the your loop come out from the loop without comparing
it.

On Mon, Oct 1, 2012 at 8:55 AM, atul anand <atul.87fri...@gmail.com> wrote:

> n=sizeof(arr);
> n--;
>
> while(n)
> {
>      if(elem=arr[n])
>           print found;
>
> n--;
>
> }
>
> On Sun, Sep 30, 2012 at 2:56 PM, רפי וינר <rafiwie...@gmail.com> wrote:
>
>> Hi
>> i was in an interview and was given a simple function
>> int arrExsits(int* arr,int size,int elem){
>> for (int i=0;i<size;++i)
>>     if(elem==arr[i])
>>        return i;
>> return -1;
>> }
>> this function does 2n compares
>> n- the if statment
>> n-check that i is smaller then size
>> i was suppose to give an optimal (less compares) solution so i gave
>>
>> int arrExsits(int* arr,int size,int elem){
>> if (arr[size-1]==elem)
>>     return size-1;
>> arr[size-1]=elem]
>> for (int i=0;;++i)
>>     if(elem==arr[i]){
>>         if (i!=size-1)
>>             return i;
>> return -1;
>> }
>> this solution works and it has n+2 compares the first one another n and
>> the second inner if.
>> they told me it's good (and I've passed) but they told just for my
>> knowledge that there is a better N compare solution.
>> I've searched the web but couldn't find it.
>> anybody knows?
>> Thanks
>>
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