@Rafi: Try this:
int arrExsits( int* arr, int size, int elem)
{
int temp = arr[0];
arr[0] = elem;
while( arr[--size] != elem );
arr[0] = temp;
return a[size] == elem ? size : -1;
}
n+1 comparisons, and it leaves the array unaltered.
Dave
On Sunday, September 30, 2012 4:27:27 AM UTC-5, rafi wrote:
> Hi
> i was in an interview and was given a simple function
> int arrExsits(int* arr,int size,int elem){
> for (int i=0;i<size;++i)
> if(elem==arr[i])
> return i;
> return -1;
> }
> this function does 2n compares
> n- the if statment
> n-check that i is smaller then size
> i was suppose to give an optimal (less compares) solution so i gave
>
> int arrExsits(int* arr,int size,int elem){
> if (arr[size-1]==elem)
> return size-1;
> arr[size-1]=elem]
> for (int i=0;;++i)
> if(elem==arr[i]){
> if (i!=size-1)
> return i;
> return -1;
> }
> this solution works and it has n+2 compares the first one another n and
> the second inner if.
> they told me it's good (and I've passed) but they told just for my
> knowledge that there is a better N compare solution.
> I've searched the web but couldn't find it.
> anybody knows?
> Thanks
>
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