ch=i++[s]; // in this value is assigned first and then increment will
take place...bcozz you are using post increment.
here i does not have any other option it has to do post increment
before [] comes...but it will not assign value to 'i' ( i.e
incremented 'i' value)
so compiler will do something like this
ch=*(i + s);
i=i+1;
ch=++i[s]; // in this case compiler will rewrite it to something like this ,
ch=++(*(i+s)); // this will increment the value at i[s], pre-increment
is taking place ...so updated i[s] value will be assigned o ch
if you do somthing like this :-
ch=i[s]++; // here post increment is happening , so compiler will
rewrite it somthing like this
// ch will contain old value but if you print i[s] , it will print
incremented value of i[s];
ch=*(i+s);
i[s]=i[s] + 1;
On 10/6/12, rahul sharma <rahul23111...@gmail.com> wrote:
> char ch
> ch=i++[s];
>
> printf("%c",ch); this will print i[s],then i is incrementrd after
> assigning to ch....
>
>
> ch=++i[s];// this will inccrement value at i[s]
>
>
> My question is what is role of priority which is making them behaving
> different,,,,I am not getting y not first i is incremented then i[s] is
> assigned....
> plz tell
>
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