Sorry, I don't understand your question. *%.2x *is only a precision specifier still. (%.2x was used for neat formatting only, because you are printing the values only 1 Byte long and a Byte can occupy at max 2digits in hex)
>>>>hex representated by 4 bits. Yes hex is represented by 4 bits i.e. 1 Byte and that's what you are reading with a char pointer*, 1 Byte each time and printing the values in those Bytes. >>>>total we have to represent 32 bits and 8 bits in each....plz xplain Each output represents 32bits only. 1 Byte each (in total 4Bytes) It's showing you the memory layout. You stored *i = 1; *and when probed it using a char pointer. you found following four bytes written: *01 00 00 00* It shows that on your machine: 1. int is 4bytes long. (4x1Byte) 2. First byte stores the least significant value, hence you are working on a Little endian machine. similarly, for pointer: char pointer reads 1 Byte at a time. It read 4Bytes in total i.e. 32 bits. Hence, you are working on a 32 bit machine. (as pointer has value: *44 ff 28 00, *address of i)*.* * * * * PS: This is an algorithm group, please refrain from asking such language specific questions. On 21 October 2012 00:19, rahul sharma <rahul23111...@gmail.com> wrote: > Actually i have taken form http://www.geeksforgeeks.org/archives/730 > Please explain me o/p...as hex representated by 4 bits....then how cum is > following o/p > 00 00 80 3f > 01 00 00 00 > 44 ff 28 00 > 01 00 00 00 > > total we have to represent 32 bits and 8 bits in each....plz xplain > > On Sun, Oct 21, 2012 at 12:05 AM, rahul sharma <rahul23111...@gmail.com>wrote: > >> void show_bytes(byte_pointer start, int len) >> { >> int i; >> for (i = 0; i < len; i++) >> printf(" %.2x", start[i]); >> printf("\n"); >> } >> >> >> >> byte_pointr is unsigned char *...typedef unsigned char * byte_pointer.... >> plz tell me use of %.2x i knowx is for hexa........does it mean print 8 >> bites of address in 4 hexa of 2 bits???i cant get xactly plz explain >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
