@Atul: Try x = 0, a = 1, b = 2, for which (x > a && x < b) is false, but (x - a < b - x) is true. Dave
On Saturday, October 27, 2012 5:43:17 AM UTC-5, ATul SIngh wrote: > Thnks but i figured it out > as > ( x >= a && x < b ) > or > ( x >= a && x <= b ) > > could be written as > x -a < b - x for first case > x -a <= b - x for sec one > > Second set is more optimised as it contains only one comparison and > minus is much efficient than comparison operator. > > > > -- > > *ATul Singh** Software Engineer**, Interra Systems* > Mobile : +91-9971794013 > www.interrrasystems.com > [image: Facebook] <http://www.facebook.com/atulsingh7890> [image: > Twitter]<http://www.twitter.com/atulsng> > [image: LinkedIn] <http://www.linkedin.com/in/atulsingh7890> > > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/pyvTrbonkq4J. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
