Saurabh your solutions seems right , but can u explain me how did u arrive
at the time and space complexity with some proof /pseudocode/ explanation?


On 15 December 2013 09:47, Saurabh Paliwal <[email protected]>wrote:

> what is the issue with the usual recurrence :-
>
> Let answer[i][j] represent minimum cost of coloring i houses with ith
> house colored with jth color.
>
> answer[i][j] = min(answer[i-1][t]) + colorvalue[t] where t varies from 1
> to k except j.
>
> initial setting :-  answer[1][j] = colorvalue[j]
>
> final answer is min(answer[n][j]) for all j from 1 to k.
>
> Time complexity = O(n*k*k)
> Space complexity = O(k) if only 2 rows are taken ( effectively only 2 are
> required ).
>
>
> On Sun, Dec 15, 2013 at 12:44 AM, kumar raja <[email protected]>wrote:
>
>> You have 'n' houses and 'k' colors. The cost of coloring a house with one
>> of the 'k' colors is different from coloring another house with same color.
>>  The cost of coloring the house with different colors are different. So now
>> how to colour the 'n' houses such that no two adjcent houses will get the
>> same color and the total coloring cost for 'n' houses is minimized.
>>
>>
>>
>> Regards,
>> Kumar Raja.
>>
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>
>
>
> --
>  -    Saurabh Paliwal
>
>        B-Tech. Comp. Science and Engg.
>
>        IIT ROORKEE
>
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