Equivalent to solving an infix expression using stack with a pair (first variable, second constant) as the element
On Sat, Jan 11, 2014 at 6:50 AM, atul anand <[email protected]> wrote: > Hello, > > How to solve an equation with one unknown variable ? > operator allowed are : + , - > > for eg . input could be :- > x + ( 5 + 4 ) = 6 > (x - 7) + 7 = (x + 1) - 5 > > If operator also allows " * " (multiply) , then what change in algorithm > is required. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected].
