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------- Additional comments from [EMAIL PROTECTED] Wed Apr 18 12:11:39 +0000 2007 ------- Is there a need for the empty selection if more than one ranges selected? I think no. So the logical results should be oSelection.getCount() - oSelection.hasElements() . 0 - False . 1 - True . 2 - True . ... Or even because there are always at least one (empty) selection: . 1 - False . 1 - True . 2 - True . ... If there is any need for the empty selection if any is selected (but IMO there isn't), then it should also _always_ exist: . 1 - True . 2 - True . 3 - True . ... But not 1 - 1 - 3 - 4 - ... as now! Sub Testselect Dim oDoc As Object Dim oSelection As Object Dim i As Integer Dim s As String oDoc = ThisComponent oSelection = ThisComponent.getCurrentSelection() If oSelection.hasElements() Then For i = 0 To oSelection.getCount() - 1 oSelection.getByIndex( i ).setString( "<--- " & Format( i, "00" ) & " --->" ) Next i MsgBox( s ) Else MsgBox( "no selection" ) End If End Sub With this sample you can see that it counts 0 0 1 - 2+0 1 - 2 - 3+0 1 - 2 - 3 - 4+0 But i can't see the logic and need for the "+0". --------------------------------------------------------------------- Please do not reply to this automatically generated notification from Issue Tracker. Please log onto the website and enter your comments. http://qa.openoffice.org/issue_handling/project_issues.html#notification --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
