To comment on the following update, log in, then open the issue:
http://www.openoffice.org/issues/show_bug.cgi?id=82420
------- Additional comments from [EMAIL PROTECTED] Thu Nov 1 05:45:20 +0000
2007 -------
I worked this around by using enumeration to get accurate section order,
something like the following :
Dim sect
sect=thisComponent.getTextSections().getByName("root")
Dim sectRange
sectRange = sect.getAnchor()
Dim sectText
sectText = sectRange.getText()
dim prevSection
prevSection = "root"
Dim sectEnum
Dim orderStr
orderStr = ""
sectEnum = sectText.createEnumeration()
while (sectEnum.hasMoreElements() )
dim nextElem
nextElem = sectEnum.nextElement()
if (Not isnull(nextElem.TextSection)) then
if (not IsEmpty(nextElem.TextSection)) then
dim tSect
tSect = nextElem.TextSection.Name
orderStr = orderStr + tSect + chr(13)+chr(10)
end if
end if
wend
msgbox orderStr
this would work even for frames since enumeration relies on visible structure
of the document. Its more
tedious, and definitely slower but it works. You would just need to check for
TextFrame objects in the
main enumeration loop, and enumerate for sections within those.
---------------------------------------------------------------------
Please do not reply to this automatically generated notification from
Issue Tracker. Please log onto the website and enter your comments.
http://qa.openoffice.org/issue_handling/project_issues.html#notification
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
