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http://www.openoffice.org/issues/show_bug.cgi?id=18134
------- Additional comments from [EMAIL PROTECTED] Sat Apr 30 10:48:33 -0700
2005 -------
I would like an 'IP Address' number format. This can be stored internally as a
regular number (as I believe dates are) but displayed and entered as an ip
address (10.1.1.45)
Here is some sample C++ that does the conversions
#include <iostream>
#include <string>
using namespace std;
int main()
{
unsigned long number = 0;
int tmp = 0, dots = 0;
string ip;
/* Parse IP Address
* Algorithm summary:
*
* Browse over each character in the input.
* Build a number until a dot is encountered or the number goes out of range.
* Repeat until end of string
* If an invalid character is found, bail out.
*/
cin >> ip;
for (int i = 0, j = ip.length(); i < j; i++)
{
// cout << i << ": " << ip[i] << endl;
if (ip[i] >= '0' && ip[i] <= '9')
{
tmp = tmp * 10 + (ip[i] - '0');
if (tmp > 255)
{
cout << "parse error: value out of range\n";
return 3;
}
// cout << "tmp: " << tmp << endl;
continue;
}
if (ip[i] == '.')
{
number *= 256;
number += tmp;
tmp = 0;
dots++;
// cout << "number; " << number << endl;
continue;
}
cout << "parse error on character " << i << "\n";
return 1;
}
if (dots != 3)
{
cout << "parse error: incorrect format\n";
return 2;
}
number *= 256;
number += tmp;
tmp = 0;
cout << number << endl;
/* Format IP Address
* Algorithm summary:
*
* Extract each portion of the number and display.
*
* I think there may be a better way to do this by shifting bits then mod 256
*/
// cin >> number;
tmp = (number - (number % 16777216)) / 16777216;
cout << tmp << ".";
number %= 16777216;
tmp = (number - (number % 65536)) / 65536;
cout << tmp << ".";
number %= 65536;
tmp = (number - (number % 256)) / 256;
cout << tmp << ".";
number %= 256;
cout << number << endl;
return 0;
}
I'm not sure if this is closely related enough to this issue or not. Should I
file a new issue specific to ip addresses?
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