At Mon, 17 Sep 2001 19:49:55 -0600,
Jack Moffitt wrote:
> 
> > In theorecially maximum case:
> > 
> >     max D = (freq * t / pepriod) * max(x, y) / x^2
> > 
> >     max D = .851 msec
> > 
> > This looks reasonable?
> 
> Yes. That results in 255.3ms of drift over 5 minutes.  That sounds
> right.

Ah, I meant that total .851 msec for 5 minutes.
Thus it's still enough small.  Sorry, I was too lame.

I guess the problem is hidden somewhere in other place..


Takashi

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