Welcome Axel - Here are some suggestions:
1. Change the host entry in your disklist file from 'localhost' to the machine's name, preferably it's FQDN. 2. Confirm your amandad entry in inetd.conf is correct and then do a 'kill -HUP ' on the inetd process. If there was an error in your amandahosts entry it would give a different error, like this: ERROR: fred: [access as operator not allowed from operator@fred] amandahostsauth failed -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Doug Silver Network Manager Urchin Corporation http://www.urchin.com ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ On Mon, 15 Apr 2002, Axel Schaefer wrote: > Hi amanda-users. > > I'm new to Amanda and want to use it for some backups. In the first (and > yet the only) case, the backup server is equals the backup client. I know, > that my question is a FAQ, but the Answers on FAQ-O-MATIC didn't solve the > problem (so, this is a NEWBIE-ALERT! =;-)). > > If I try to use: > > amanda@linux:> amcheck -c DailySet1 > > the following error appears: > > /----------------------------------------------------------------- > | Amanda Backup Client Hosts Check > | -------------------------------- > | WARNING: localhost: selfcheck request timed out. Host down? > | Client check: 1 host checked in 30.007 seconds, 1 problem found > | > | (brought to you by Amanda 2.4.2p2) > \----------------------------------------------------------------- > > I've checked the inetd.conf, and I think, that the amanda.conf in > /etc/amanda/DailySet1 is OK. I only set new paths to the infofile, logdir, > indexdir, tapelist. > The .amandahosts (in var/lib/amanda) shows this: > > amanda@ll11:~> less .amandahosts > localhost amanda > localhost root > > I've commented out both lines and tried it with only root-access and > amanda-access. IIRC, amanda uses one line for the client (root) and one > line for the server (amanda). So it seems OK, if localhost amanda is set > (isn't it?). > > I'm a bit irritated if the the server-client works properly, when it's is > on one computer. Can you help? > > Thanks. > AxxL >
