On Friday 24 January 2003 05:35, Scott Mcdermott wrote: >dalton on Fri 24/01 09:59 +0100: >> But we have a 100mbit LAN, so there should be 10240 kbps, thats >> right? > >just being picky, > >$ bc -ql >100 * (2^10)^2 / 8 / 2^10 >12800.00000000000000000000 > >:) of course if you actually hit that wire speed I'll be amazed. > I don't believe this is quite correct. Thats a serial protocol, and AFAIK it still uses start and stop bits, so the real /8/ divisor above should probably be /10/, giving a 10 megabytes or 100 megabaud a second rate, hence the naming convention.
-- Cheers, Gene AMD K6-III@500mhz 320M Athlon1600XP@1400mhz 512M 99.22% setiathome rank, not too shabby for a WV hillbilly
