Subin, Looks like you might have to install the handler: Here's the snippet from python docs:
======== # create a password manager password_mgr = urllib2.HTTPPasswordMgrWithDefaultRealm() # Add the username and password. # If we knew the realm, we could use it instead of None. top_level_url = "http://example.com/foo/"; password_mgr.add_password(None, top_level_url, username, password) handler = urllib2.HTTPBasicAuthHandler(password_mgr) # create "opener" (OpenerDirector instance) opener = urllib2.build_opener(handler) # use the opener to fetch a URL opener.open(a_url) # Install the opener. # Now all calls to urllib2.urlopen use our opener. urllib2.install_opener(opener) ======== thanks mahadev On Fri, Mar 15, 2013 at 2:50 AM, Modeel, Subin <[email protected]> wrote: > Hi > I was trying to invoke the rest call from python-urllib2 .I see that It fails > with 403 error.I feel its because there is no realm value. > I am unable to find the WWW-Authenticate: value to find the realm value. > Can you please help me with this. > > > Thanks > >>>> import urllib2 >>>> url = 'http://localhost:8080/api/v1/clusters/' >>>> password_mgr = urllib2.HTTPPasswordMgrWithDefaultRealm() >>>> handler = urllib2.HTTPBasicAuthHandler(password_mgr) >>>> password_mgr.add_password(None,'http://localhost:8080','admin', 'admin') > >>>> opener.open('http://localhost:8080/api/v1/clusters/') > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > File "/usr/lib64/python2.6/urllib2.py", line 397, in open > response = meth(req, response) > File "/usr/lib64/python2.6/urllib2.py", line 510, in http_response > 'http', request, response, code, msg, hdrs) > File "/usr/lib64/python2.6/urllib2.py", line 435, in error > return self._call_chain(*args) > File "/usr/lib64/python2.6/urllib2.py", line 369, in _call_chain > result = func(*args) > File "/usr/lib64/python2.6/urllib2.py", line 518, in http_error_default > raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) > urllib2.HTTPError: HTTP Error 403: Full authentication is required to access > this resource > > > > I am able to use the pycurl library to get the response. > > >>>> import pycurl, json >>>> url = 'http://localhost:8080/api/v1/clusters/' >>>> c = pycurl.Curl() >>>> c.setopt(pycurl.URL, url) >>>> c.setopt(pycurl.USERPWD,'admin') >>>> c.setopt(pycurl.USERPWD,'admin:admin') >>>> c.perform() > { > "href" : "http://localhost:8080/api/v1/clusters/";, > "items" : [ > { > "href" : "http://localhost:8080/api/v1/clusters/test1";, > "Clusters" : { > "cluster_name" : "test1", > "version" : "HDP-1.2.0" > } > } > ] > }
