Re: Call for bikeshed -- break replacement in expression switch

[Dan Smith]

> On May 16, 2019, at 2:28 PM, John Rose <john.r.r...@oracle.com> wrote:
> 
> Chapter 1.  Some constructs have arrows.
> They define when the arrow bodies are executed,
> and, if the the arrow gets tossed a value, what
> is done with that value (method return?
> switch result? block result? depends on 
> where the arrow is).
> 
> Chapter 2.  Every yield matches an innermost
> arrow, and every arrow (in a non-void T context)
> accepts a yielded value (of type T).

Reminder: the <break replacement> statement can be used in two contexts: 
arrow-based switch rules and label-based switch blocks.

int i = switch (foo) {
    case "a" -> { yield 1; }
    case "b" -> { yield 2; }
    default: -> { yield 0; }
};

int j = switch (foo) {
    case "a": yield 1;
    case "b": yield 2;
    default: yield 0;
};