Sure !
I had understand before when you told me about that, but i am 
understand more and more about this problem of precision for 
multiple recursion with some power on them.
Solution if i am right : center the data on the time axis and 
normalise their value the nearer from [-1;1].

Just one question, i have seen you use often iniatialize with "X=Cum
(0)" instead of "X=0". It seems the same (X=0, put 0 on all the bar 
of X). It is because it react differently if QuickAFL is on/off 
(SetBarsRequired) and with Cum(0) you are sure to fill all the bars ?





--- In [email protected], "Fred" <[EMAIL PROTECTED]> wrote:
>
> Possibly you understand now why in Gaussian Elimination I chose to 
> arbitrarily set the midpoint along the x-axis to zero and keep the 
> numbers along the scale in fairly tight range, and perform the 
calcs 
> in double precission ... yes ?
> 
> --- In [email protected], "Tom Tom" <michel_b_g@> wrote:
> >
> > So after further investigation.
> > 
> > 
> > I code loop in VBS double. Result is not the same than SUM, nor 
> FOR.
> > So SUM or FOR are not exact, but they act not the same in 
> rounding. I thing 
> > the arythmetic order to calculate is not the same in FOR and in 
> SUM so 
> > rounding are different, so result are different.
> > But one or other, result is not accurate.
> > If I want to stay in AFL and I had to choose between SUM and 
FOR, 
> wich one I 
> > will go ? As they are both innacurate, SUM seems better ?
> > 
> > 
> > I test max/min number for AFL after reading the link from Paul : 
> > http://en.wikipedia.org/wiki/IEEE_754
> > 
> > Code :
> > 
> > ieee = -1e10;
> > _TRACE("IEEE:"+ ieee); // to show exponent
> > _TRACE("IEEE:"+ NumToStr(ieee,1.9) ); // to show innacurate digit
> > 
> > And try after with :
> > ieee = 1e11;
> > 
> > exponant should go from -126 to +127, but in our case :
> > ieee = 1e-10; -> result are infinite
> > ieee = 1e11; -> ok for direct trace, but with numtostr there is 
> rounding and 
> > do not use exponent notation
> > ieee = 1e39; -> result are infinite
> > 
> > So my question, wy exponent go from -10 to 39 !?
> > And NumToStr(x,1.9), seems to send back rounding result. Cannot 
it 
> send back 
> > with exponent notation and no rounding like direct _trace ?
> > 
> > Second, accuracy seems 7 digit, but it should be 6 digit ? (max 
> number from 
> > the mantisse is 2^23 - 1 = 8388607, that give 7 number so six 
> digit sure).
> > Try: ieee = 99999981
> > 7th digit is ok. 8th digit is wrong.
> > 
> > So AB use wich encoding (not IEEE_754 ?) and difference between 
> direct 
> > _trace and _trace with NumToStr come from NumToStr wich make 
> rounding for 
> > big exponent ?
> > 
> > Cheers,
> > Mich.
> > 
> > _________________________________________________________________
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> depuis votre 
> > mobile comme sur PC ! http://mobile.live.fr/messenger/bouygues/
> >
>



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