In the help for linregintercept is this code for plotting the line
x = Cum(1);
lastx = LastValue( x ); Daysback = 10; aa = LastValue( LinRegIntercept(
Close, Daysback) );
bb = LastValue( LinRegSlope( Close, Daysback ) );

y = Aa + bb * ( x - (Lastx - DaysBack) ); Plot( Close, "Close", colorBlack,
styleCandle );
Plot( IIf( x >= (lastx - Daysback), y, -1e10 ), "LinReg", colorRed );


If you just want the linear reg values plotted, like a moving average just
use
Plot( LinearReg( close, 10 ), "LinReg", colorRed );


--
Cheers
Graham
AB-Write >< Professional AFL Writing Service
Yes, I write AFL code to your requirements
http://www.aflwriting.com

On 18/11/06, Charles J. Dudek <[EMAIL PROTECTED]> wrote:

OK, so how do I fix it?  Do I have to write some code that will
calculate a least squares regression from scratch?  I think that will
be really hairy to try to figure out.  Are there any examples of
formulas written to do the same thing or something similar?  None of
the linearreg formulas on the AB website helped.

--- In [email protected], "Fred" <[EMAIL PROTECTED]> wrote:
>
> From the doc ...
>
> SYNTAX  LinRegIntercept( ARRAY, periods )
>
> RETURNS ARRAY
>
> --- In [email protected], "Charles J. Dudek" <trader@>
> wrote:
> >
> > And how do I fix it.  I'm getting a type mismatch error, but I
> can't
> > see where I'm trying to put an entire array into one cell.
> >
> > aL[i]   =  LinRegIntercept( C [i] , Longcount[i] );
> >
> > Does LinRegIntercept create an array?  If so, how do I get around
> > that?  I'm trying to create trendlines at various points throughout
> > the history that start and end based on other calculations.  This
> is
> > driving me CRAZY!!!
> >
> > Are there any examples of this kind of thing I could refer to?  I
> know
> > I could use LineArray, but I also need to calculate standard
> > deviations based on the same periods, so I don't think that will
> help
> > me, will it?
> >
> > Chuck
> >
>





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