Hi Graham,
                 i've put together a volatility breakout system that i'm having 
fun with back testing,,,it buys at a calculation above the bar,,,used 
buyprice=calculation.It sells using sell=barssince(buy)== number of days

   what i'd like to do next is apply a fixed stop below the buy bar incase of a 
reversal,,,and i'd like to nominate a calculation for that stop price.

the stop isn't a fixed percentage or a trailing stop but a calculation that is 
the inverse of the buy calculation ,,,the buy side works so i know i've got my 
calculation written correctly,,,which in its self was a learning curve learning 
the B.E.D.M.A.S

i read up on applystop and thought i could use that function,,,so i'm after a 
stop by calculation that's fixed ie doesn't trail or move and is defined by my 
calculation,,,,and is exit on stop.

this is where i got to
  applystop(type,mode,amount,exitatstop,volatile,reentrydelay)

type=0 //maxstoploss
mode ,,,??
amount,,,??? somehow i need to introduce the calculation here i think ???
exitatstop=1 ,,,,true exit on stop price
volatile=false
reentrydelay=0

over
Paul

   


  more detail required, by me at least, as I am not sure what conditions you 
require for the stop to be used


  -- 
  Cheers
  Graham
  AB-Write >< Professional AFL Writing Service
  Yes, I write AFL code to your requirements 
  http://www.aflwriting.com 



  On 17/01/07, paulradge <[EMAIL PROTECTED]> wrote:
    ooooooooooopppssss
               no it doesn't,,,can someone give me a pointer here please,,,
    P



      never mind it works,,,

        ----- Original Message ----- 
        From: paulradge 
        To: [email protected] 
        Sent: Wednesday, January 17, 2007 2:14 PM
        Subject: [amibroker] Apply stop question


        i've just read the apply stop help,,,and need halp with a question 
please.

        re mode,,,
        i want my stop to be a calculation should i select 0 = disablestop

        re amount,,,
        i want my stop to be a calculation ,,,is this ok = Y 
        ,,,,y=calculation

        if so would this be correct,,,

        applystop(0,0,Y,1,false,0)

        action,
        max loss stop,,disable stop,y=calculation,exit on stop price,fixed 
        stop,
        no re entry,

        regards
        Paul










   

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