there are different ways to achieve things, for simple conditions to give true/false result you can simply use statement with OR/AND. The following assigns true to results if all 3 conditions are true on the same bar
Result = Trigger AND C1 AND C2; to assign values to the variable for true/false result, these values can be arrays are scalar Result = iif( Trigger AND C1 AND C2, A, B ); Nested IIF can also allow you to work through combinations of the conditions to give different resulting values. Just by placing the more stringent first and work from there Result = iif( Trigger AND C1 AND C2, A, iif( Trigger AND C1, B, iif( Trigger AND C2, C, iif( C1 and C2, D, E )))); These are much easier and straightforward than looping. I only use loops if the results I want depend on previous values of the same array for the current value, or to isolate a particular repeating occurence to only use the first occurence and ignore the rest (where other simple methods do not work). Loops can slow down the running of AFL and best to be avoided unless really necessary. They can also tie your brain up in knots getting the logic correct when a simple method is easier and faster. -- Cheers Graham Kav AFL Writing Service http://www.aflwriting.com On 26/08/07, lifes_student_1 <[EMAIL PROTECTED]> wrote: > It's a bit more complicated than my example. I need to check for > several cases and I would generally use an if statement for something > like this. Something like: > > result = false; > if (trigger == true) > { > if (c1 == true) > { > if (c2 == true) > { > result = true; > } > } > } > > --- In [email protected], Graham <[EMAIL PROTECTED]> wrote: > > > > Not knowing what you are trying to do why not try the simpler and > > faster IIF function > > > > -- > > Cheers > > Graham Kav > > AFL Writing Service > > http://www.aflwriting.com > > > > > > > > On 26/08/07, lifes_student_1 <[EMAIL PROTECTED]> wrote: > > > Thanks. Why can't I do the following though that should result in > a > > > boolean: > > > > > > color = colorLime; > > > color2 = colorRed; > > > i1 = colorLime; > > > c1 = ((i1 == color OR i1 == color2)); > > > if (c1 == true) > > > {... > > > > > > > > > This doesn't work. I guess I'm not used to AFL. > > > > > > > > > > > > --- In [email protected], "Thomas Z." <tzg@> wrote: > > > > > > > > You need a loop and then you could write if(barsback[i] < 6) > > > > > > > > The other way would be to use IIF() > > > > > > > > Regards > > > > Thomas > > > > www.patternexplorer.com > > > > > > > > > > > > > > > > From: [email protected] > [mailto:[EMAIL PROTECTED] > > > On Behalf > > > > Of lifes_student_1 > > > > Sent: Saturday, August 25, 2007 8:28 PM > > > > To: [email protected] > > > > Subject: [amibroker] getting an error in my if statement > > > > > > > > condition1 = cross(close, ma(close,20)); > > > > barsback = BarsSince(condition1 == true); > > > > if(barsback < 6) > > > > {... > > > > > > > > I'm getting error 6 on barsback in if statement. condition1 is > set > > > and > > > > works as I've tested it elsewhere. What am I doing wrong? > > > > > > > > (Condition in IF, WHILE, FOR statements has to be Numeric or > > > Boolean > > > > type. You cannot use an array here....) > > > > > > > > > > > Please note that this group is for discussion between users only. > > To get support from AmiBroker please send an e-mail directly to > SUPPORT {at} amibroker.com > > For NEW RELEASE ANNOUNCEMENTS and other news always check DEVLOG: > http://www.amibroker.com/devlog/ > > For other support material please check also: > http://www.amibroker.com/support.html > > Yahoo! Groups Links > > > >
