Thomas, could you explain this further please?

Using this example:
x = valuewhen(y, z, 1);

Wouldn't x be the exact value of z for the same bar as the first y==1? How does 
that return an array? If so, how do I "iterate through the values"?

Thanks!




--- In [email protected], "Thomas Z." <t...@...> wrote:
>
> Valuewhen returns a array, therefore you would need to iterate through the
> values.
> 
>  
> 
> 
> SYNTAX 
> 
> valuewhen(EXPRESSION, ARRAY, n = 1) 
> 
> 
> RETURNS
> 
> ARRAY 
> 
> 
> FUNCTION 
> 
> Returns the value of the ARRAY when the EXPRESSION was true on the n -th
> most recent occurrence. Note: this function allows also 0 and negative
> values for n - this enables referencing future 
> 
> 
> EXAMPLE
> 
> valuewhen( cross( close, ma(close,5) ) ,macd(), 1) 
> 
>  
> 
>  
> 
>  
> 
> Thomas
> 
> www.PatternExplorer.com
> 
>  
> 
>  
> 
> -----Original Message-----
> From: [email protected] [mailto:[email protected]] On Behalf
> Of lucianomt
> Sent: Thursday, June 25, 2009 11:00 PM
> To: [email protected]
> Subject: [amibroker] Valuewhen issue
> 
>  
> 
> t = array with all troughs
> 
> p = array with all peaks
> 
>  
> 
> tbar = ValueWhen(t, BarIndex(), 1);  
> 
> pbar = ValueWhen(p, BarIndex(), 1);
> 
> if(pbar < tbar)
> 
> {
> 
> [CODE]
> 
> }
> 
>  
> 
> I have two arrays marking all the peaks and troughs, respectively,
> previously filled with ZigZag. I want to check whether the peak or trough
> comes first, so I tried to get the respective bars using Valuewhen and then
> checking using IF.
> 
>  
> 
> Why am I getting an error 6 message on the IF statement? I thought ValueWhen
> returned a specific value not an array...
> 
>  
> 
>  
> 
>  
> 
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