The response I liked best (and was closest to what I recall) was less than
50 microamps at full rated voltage....
73, Barrie, W7ALW
Whatever amount of leakage current you decide would be acceptaable, it would
be proportional to the capacitance. A 2 mfd capacitor would be expected to
have much lower leakage current than a 50 mfd one at the same voltage rating
and test voltage.
For example, think of a 20 mfd cap as equivalent to ten 2-mfd caps wired in
parallel. So you would expect 10 times the leakage current with the 20 mfd.
Don k4kyv
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