[EMAIL PROTECTED] wrote:
> Ok, I figured it out!
>
> I was reading the perl documentation on the "localtime" function, and it
> mentions that to get the last two digits in the year you would do:
>
> $year = sprintf("%02d", $year % 100);
>
> So I figured, maybe this will work for the month and day. I created the
> following perl script:
>
> @d = localtime;
> $mm = sprintf("%02d", ($d[4]+1) % 100);
> $dd = sprintf("%02d", $d[3] % 100);
> rename $ARGV[0], "$ARGV[0].".($d[5]+1900).$mm.$dd;
>
> This did pretty much what I expected, but I have to admit I'm not sure
> exactly how. It appears that I am telling it to convert the variable into a
> percentage and then taking only the last two characters. I tested it by
> setting the date to something with a 2 digit month and day (Nov 27) and it
> still worked.
Actually "%02d" is a printf/sprintf formatting specification say
"produce a decimal with at least two digits to the left of the decimal
and use 0's for left padding." For more information on these format
specs see your favorite C programming tutorial or reference.
Jeremy Wadsack
Wadsack-Allen Digital Group
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