Can you help me match a literal ? in a regular expression? Looking for \? doesn't match anything at all, I think analog is looking for one or more repetitions of the backslash.

I have also tried \?{1}

I want to match on URLs that have a single ? in them at a certain place, but not just anywhere. The reason is that I'm using URL parameters to track my ads, and in ads for http://www.goingware.com/tips/ I have ads with URLs for the form:

http://www.goingware.com/?s=1&d=3&t=7

The parameters encode variants of my ads that I've tried, and my object is that I can make quick reports on all my ads with a Python script (which I have yet to write).

Here are the relevant lines from my config file:

FILEEXCLUDE /*
FILEINCLUDE /tips/
FILEINCLUDE /tips/\?{1}*

I have also tried

FILEINCLUDE /tips/\?*

and it doesn't match anything.

Thanks for any help you can give me.

Michael D. Crawford
[EMAIL PROTECTED]

   Read "GoingWare's Bag of Programming Tricks" at:
          http://www.goingware.com/tips/
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