Typically you call your current activity's startActivity() method to
switch to another activity. That method can accept an instance of
Intent class, which in turn enables you to put some data in the intent
object before you call startActivity. Check out the documentation of
Bundle class and you'll see that it's got a lot of put... methods (and
the corresponding get... methods, too). So for example you could call
putIntArray method which adds an int array to the bundle. E.g.:
int[] ia = {1, 2, 3};
Intent i = new Intent();
Bundle b = i.getExtras();
b.putIntArray("myIntArray", ia);
startActivity(i, MyActivity2.class);
Similarly, on the receiving end you can use getIntArray to get your
data. The disadvantage of this solution is that whenever the data
changes on one end you've got to update the other end, too, because it
doesn't happen automatically.
Another approach would be to use a singleton to store information that
shall survive activity changes. In this case both ends access the same
information and since no two activities can live at the same time you
don't even need to bother with synchronization issues.
On Feb 15, 11:58 am, madcoder <[email protected]> wrote:
> Could you give a more detailed example - I too would like to see how
> an array (of ints, for example) can be accessed in activity 2 from
> activity one. As it is now, I'm loading that data every time I start
> a new activity - and it's quite slow!
>
> Thanks
>
> On Feb 14, 7:32 pm, Ganesan V <[email protected]> wrote:
>
> > U can use Indent class of MyActivity from MyActivity2.
>
> > Ganesh.
>
> > On Sat, Feb 14, 2009 at 2:05 AM, Alex55 <[email protected]> wrote:
>
> > > Hello guys,
>
> > > I have a very basic question regarding Activities in Android.
>
> > > Can I share data types a cross Activities in Android?
>
> > > Let's say I have 2 activities, MyActivity.java and MyActivity2.java. I
> > > have declared some Strings and Arrays on MyActivity that I would like
> > > to access from MyActivity2, is this possible? If so, how can I
> > > accomplish this?
>
> > > I know its a very basic question, but believe it or not I've had a
> > > hard time figuring this one out!
>
> > > Many thanks for your prompt response,
>
> > > Alex
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