Yep that is what I vaguely based mine on. I recognize the Praeda line. I had to modify mine because I was not sending back an array of json objects but a specific one that I handle based on the ID on the backend with ruby.
On Wed, Sep 9, 2009 at 1:43 AM, Alok Kulkarni <kulsu...@gmail.com> wrote: > Hey Wayne, thanks a lot.. > I have also got a solution parallely which i would like to post > > URL url = new URL(serverURL); > > // open the conncetion > HttpURLConnection connection = > (HttpURLConnection)url.openConnection(); > > // Let the run-time system (RTS) know that we want input. > connection.setDoInput(true); > // Let the RTS know that we want to do output > connection.setDoOutput(true); > // No caching, we want the real thing > connection.setUseCaches(false); > // set the content type property > connection.setRequestProperty("Content-type",strContenttype); > > // set request method > connection.setRequestMethod("POST"); > // create the post body to send > String content = credDevPair.toString(); > Log.i("Request ====....... ",content); > DataOutputStream printout = new DataOutputStream ( > connection.getOutputStream () ); > > // send the data > printout.writeBytes(content); > printout.flush(); > printout.close(); > String output = > convertStreamToString(connection.getInputStream()); > Log.i("Response 1....... ",output); > // A Simple JSONObject Creation > JSONObject json=new JSONObject(output); > > Log.i("Praeda","<jsonobject>\n"+json.toString()+"\n</jsonobject>"); > > // A Simple JSONObject Parsing > JSONArray nameArray=json.names(); > JSONArray valArray=json.toJSONArray(nameArray); > for(int i=0; i<valArray.length() ;i++) > { > > Log.i("Praeda","<jsonname"+i+">\n"+nameArray.getString(i)+"\n</jsonname"+i+">\n" > > +"<jsonvalue"+i+">\n"+valArray.getString(i)+"\n</jsonvalue"+i+">"); > } > //BufferedReader input = new BufferedReader ( new > InputStreamReader(connection.getInputStream()) ); > > }catch (ClientProtocolException e) { > // TODO Auto-generated catch block > e.printStackTrace(); > }catch (IOException e) { > // TODO Auto-generated catch block > e.printStackTrace(); > > }catch(Exception ex) > { > > } > > } > private static String convertStreamToString(InputStream is) { > /* > * To convert the InputStream to String we use the > BufferedReader.readLine() > * method. We iterate until the BufferedReader return null which > means > * there's no more data to read. Each line will appended to a > StringBuilder > * and returned as String. > */ > BufferedReader reader = new BufferedReader(new > InputStreamReader(is)); > StringBuilder sb = new StringBuilder(); > > String line = null; > try { > while ((line = reader.readLine()) != null) { > sb.append(line + "\n"); > } > } catch (IOException e) { > e.printStackTrace(); > } finally { > try { > is.close(); > } catch (IOException e) { > e.printStackTrace(); > } > } > > return sb.toString(); > } > > > On Wed, Sep 9, 2009 at 3:08 AM, Wayne Wenthin <wa...@fuligin.com> wrote: > >> A snippet for what I do... >> public HttpResponse updateGirl(String url, Pawn girl, int pawnID) { >> HttpClient httpclient = new DefaultHttpClient(); >> HttpPut httpput = new HttpPut(url); >> >> // Execute the request >> >> try { >> List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>( >> 39); >> nameValuePairs.add(new BasicNameValuePair("id", Integer >> .toString(pawnID))); >> ...... Many nameValuePairs later..... >> >> >> httpput.addHeader("Content-Type", >> "application/x-www-form-urlencoded"); >> httpput.setEntity(new UrlEncodedFormEntity(nameValuePairs, >> HTTP.UTF_8)); >> HttpResponse response = httpclient.execute(httpput); >> return response; >> >> } catch (ClientProtocolException e) { >> // TODO Auto-generated catch block >> // e.printStackTrace(); >> } catch (IOException e) { >> // TODO Auto-generated catch block >> e.printStackTrace(); >> } >> return null; >> >> } >> >> Hope that helps. I struggled with it for a couple of weeks before I >> found a site that had a good source. >> >> >> >> On Tue, Sep 8, 2009 at 6:18 AM, Alok Kulkarni <kulsu...@gmail.com> wrote: >> >>> Any answers ?? >>> >>> >>> On Tue, Sep 8, 2009 at 2:00 PM, Alok <kulsu...@gmail.com> wrote: >>> >>>> >>>> I have created a JSON object which i want to send over the network to >>>> a server.Do i need to user OutputStream and BufferedOutput stream ? >>>> I have read the RestClient example which parses an incoming JSON >>>> object and retrieves the string data. But how do i send a JSON object >>>> to the server? >>>> Thanks, >>>> Alok >>>> >>>> >>> >>> >>> >> >> >> -- >> Writing code is one of few things >> that teaches me I don't know everything. >> >> >> > > > > -- Writing code is one of few things that teaches me I don't know everything. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Beginners" group. To post to this group, send email to android-beginners@googlegroups.com To unsubscribe from this group, send email to android-beginners-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en -~----------~----~----~----~------~----~------~--~---