For connecting to the localhost of your machine, you should not use
127.0.0.1

You can use the IP instead, or Please read up the docs.

http://developer.android.com/guide/developing/tools/emulator.html#networkinglimitations

Check for the section."Network Address Space"

Thanks and Regards,
Kumar Bibek.

On Jan 7, 7:15 am, Kenn Min Chong <[email protected]> wrote:
> OKOK, I think I found out what the issue is, but can't explain why. I
> was trying to connect to a webservice located on the same machine as
> the emulator was running. I tried referring to the local machine by IP
> and by name, but I always get the "no route to host" error. But when I
> connect to the same webservice, but hosted on a different machine
> altogether, it works fine! So, what am I missing here?
>
> On Jan 6, 8:55 pm, Kenn Min Chong <[email protected]> wrote:
>
> > I don't get it. I'm having this issue in the emulator. Is this an
> > emulator only issue or  it affects real devices too? This used to not
> > do this, did a recent SDK update break this functionality?
>
> > On Jan 6, 8:28 pm, Wayne Wenthin <[email protected]> wrote:
>
> > > You are not alone.   I have this every once in awhile,  I know that they
> > > have already logged in due to where it generates the error.   It's 
> > > annoying
> > > to say the least.  I'm now working on catching the exception and retrying
> > > since it is just trying to put a json object to my server
>
> > > On Wed, Jan 6, 2010 at 3:07 PM, Kenn Min Chong <[email protected]> wrote:
>
> > > > Hey guys!
> > > >   So, this is very frustrating. I already have
>
> > > > <uses-permission android:name="android.permission.INTERNET"></uses-
> > > > permission>
>
> > > > in my manifest, but when my application tries to make a webservice
> > > > call (I'm using a HttpURLConnection object to do this via connect()
> > > > method), I'm getting an exception of "No route to host".
>
> > > > The built-in Browser application is able to access the internet
> > > > properly, so I'm guessing it's something in my project. Any ideas?
>
> > > > Kenn.
>
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>
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