Thanks Mark, it works.
On Jan 9, 3:32 pm, Mark Murphy <[email protected]> wrote: > Business Talk wrote: > > How is it that I can open a file with > > > FileInputStream inputStream = _Context.openFileInput("songs.zip"); > > > but not with > > > ZipFile zipFile = new ZipFile("songs.zip"); > > > the ZipFile throws the FileNotFoundException. What am I missing? > > openFileInput() knows about /data/data/your.package.here/files. > ZipFile(), and everything else in stock Java, does not. You will need to > fully-qualify your path: > > ZipFile zipFile=new ZipFile(new File(getFilesDir(), "songs.zip")); > > -- > Mark Murphy (a Commons > Guy)http://commonsware.com|http://twitter.com/commonsguy > > _Beginning Android_ from Apress Now Available!
-- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
