Ooops, just realised I misread your post, you retrieve file from server so obviously XmlResourceParser isn't going to work for you... The principle is the same though, you need a XmlParser. Look at the doc to see if there's one that can take an input from any file and not just a resource file.
On 13 August 2010 09:03, Natalie Hooper <[email protected]>wrote: > I've done something similar in my app, I have created a separate class > called "XmlFileParser", in which I use a XmlResourceParser object to carry > out the parsing. > > > On 11 August 2010 11:34, Neilz <[email protected]> wrote: > >> In my new project I connect to a server and retreive an xml file. I >> want to populate Java objects with this data. >> >> Now, obviously, searching the net for this brings up a number of >> common solutions. But I have noted that some (e.g. Castor) look like >> they won't be suitable for Android (as it's missing certain required >> libraries) and some are actually over complex. For example, I'm not >> worried about dynamic object creation using annotations... I'll create >> the classes myself. >> >> What technology would be recommended to deal with this scenario? >> >> Thanks. >> >> -- >> You received this message because you are subscribed to the Google >> Groups "Android Developers" group. >> To post to this group, send email to [email protected] >> To unsubscribe from this group, send email to >> [email protected]<android-developers%[email protected]> >> For more options, visit this group at >> http://groups.google.com/group/android-developers?hl=en >> > > > > -- > Google Android, programming and web design at http://www.cogitas.net/blog/ > -- Google Android, programming and web design at http://www.cogitas.net/blog/ -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
