Here code in server (example.php):
< ?php
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['myFile']['name']);
if(move_uploaded_file($_FILES['myFile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['myFile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
//Text
echo $_POST['textData'];
? >
"I hope this helps"
On Sep 12, 8:43 am, David Tiago <[email protected]> wrote:
> Hello,
>
> I would like to develop an application that uploads an image and some
> text data about that image.
> To do that, I am trying to create a HTTP Multipart Post, as follows:
> [code]
> HttpClient client = new DefaultHttpClient();
> HttpPost post = new HttpPost("servlet address");
> FileBody file = new FileBody(new File("image file"));
> StringBody text = new StringBody("text data");
> MultipartEntity reqEntity = new
> MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
> reqEntity.addPart("myFile", file);
> reqEntity.addPart("textData", text);
> [/code]
>
> My doubt is: how can I extract those values in the server? I would
> like to develop a Servlet to receive and process the post requests. In
> this Servlet I would need to extract these values in th request.
> Can you help me?
> Do you have any sample of server to answer the android multipart
> requests?
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