On Tue, Oct 12, 2010 at 3:51 PM, Capt Spaghetti <[email protected]> wrote:
> HttpPost httppost = new HttpPost("graborginfo.php");
That is not a valid URL.
> HttpResponse response = httpclient.execute(httppost);
> HttpEntity entity = response.getEntity();
> InputStream is = entity.getContent();
> }catch(Exception e){
> Log.e("log_tag", "Error in http connection
> "+e.toString());
> }
> //convert response to string
> try{
> InputStreamReader is = new
> InputStreamReader(System.in);
> BufferedReader reader = new BufferedReader(is);
> StringBuilder sb = new StringBuilder();
> String line = null;
> while ((line = reader.readLine()) != null) {
> sb.append(line + "\n");
> }
> is.close();
>
> result=sb.toString();
> }catch(Exception e){
> Log.e("log_tag", "Error converting result
> "+e.toString());
> }
For this, I recommend using the BasicResponseHandler pattern:
http://svn.apache.org/repos/asf/httpcomponents/httpclient/trunk/httpclient/src/examples/org/apache/http/examples/client/ClientWithResponseHandler.java
(or http://bit.ly/lCVgZ if that URL is too long)
> The LOGCAT output for the error is as follows:
> =====================
> 10-12 11:14:08.199: INFO/global(233): Default buffer size used in
> BufferedReader constructor. It would be better to be explicit if an 8k-
> char buffer is required.
> 10-12 11:14:20.460: ERROR/log_tag(233): Error parsing data
> org.json.JSONException: A JSONArray text must start with '[' at
> character 0 of
You may want to dump the value you are trying to parse as JSON to
LogCat, as it is not what you think it is.
--
Mark Murphy (a Commons Guy)
http://commonsware.com | http://github.com/commonsguy
http://commonsware.com/blog | http://twitter.com/commonsguy
Android 2.2 Programming Books: http://commonsware.com/books
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