It just so happens that each area of the image has a specific color, so that is an excellent idea, thanks very much for your suggestion.
On Dec 6, 7:19 am, ip332 <[email protected]> wrote: > Here is a generic solution for handling any number of arbitrary shaped > hotspots: > 1) create additional bitmap (same size as what you plan to show on the > screen) and draw "hot areas" with a specific color. If you have less > than 255 hotspots then use 8bpp bitmap with background of color with > index 0. Draw the first hot spot with desired shape and color it with > index 1, then the second area - with index 2 and so on. Or you can do > it with 24bpp bitmap but assign each area a specific RGB combination. > 2) load this bitmap (let's call it "control") when your application > starts up. > 3) on screen click: convert screen coordinates into x,y from the > origin of your image (which can be larger than the screen) > 4) get pixel color from the control bitmap - if it is > 0 then it is a > hotspot index of code. > Good luck > Igor > > On Dec 5, 5:43 am, bagelboy <[email protected]> wrote: > > > I have an image and I want to make parts of it clickable. From my > > research I can see 2 ways to do this: > > 1) I could chop the image into pieces and put them into a relative > > layout > > 2) I could create a matrix of points that describe the clickable areas > > and use onTouch events to track clicks > > > Option 1 has the drawback where you have to make areas square or > > rectangular, plus alignment and scaling are a pain. > > > Option 2 can be scaled easier however I'm not sure how to go about > > coding it. > > > Am I missing any possibilities? Are there any tools or source code > > that would make it easier? > > > -BB -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
