Oops -- since the key values are Integer objects, should be something like:
return key1.compareTo(key2); On Feb 2, 6:21 am, DanH <[email protected]> wrote: > An alternative is to put your HashMaps into a regular HashMap[] array > and then use Arrays.sort. Create an external Comparator class that is > roughly: > class MyComparator implements Comparator { > public int compare(HashMap o1, HashMap o2) { > Integer key1 = (Integer) o1.get("age"); > Integer key2 = (Integer) o2.get("age"); > return key1 - key2; > > } > } > > (This can just be an extra method and interface added to your current > class, and then use your "this" pointer for the Comparator in sort(). > Or you can define and instantiate a new class.) > > On Feb 1, 10:12 pm, DanH <[email protected]> wrote: > > > You have a bunch HashMaps of different people, and you want to sort by > > age? > > > You need to spin through the list of HashMaps and extract age from > > each one, then insert the age and HashMap into, eg, a TreeMap, with > > age being the key. > > > On Feb 1, 8:15 pm, Mystique <[email protected]> wrote: > > > > Ok, I just read but unclear (java newbie) about this one: > > > > ArrayList<HashMap<String,String>> list = new > > > ArrayList<HashMap<String,String>>(); > > > > // I have a loop collecting these value from a XML parser > > > HashMap<String,String> map = new HashMap<String,String>(); > > > map.put("name",Tname); > > > map.put("age",Tage); > > > list.add(map); > > > > So let say I have test data, I want to sort the age in the ArrayList > > > call "list": > > > mary, 12 > > > john, 11 > > > > Any sample to look at? -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
