http://www.google.com/search?q=java+io+tutorial
You are not getting any errors BTW.
On 6 фев, 22:33, ROH <rhol...@gmail.com> wrote:
> Hi Fellow Android Developers,
>
> I have fairly new to the development of Android mobile applications.
> In one of my applications that I have developed, I want to consume
> a .NET web service that I have created and published to the internet.
> Below I have uploaded a sample of the code that I started. I have a
> receiving a message that I don't understand too much about. That is
> posted at the bottom of this post.
>
> import android.app.Activity;
> import android.app.AlertDialog;
> import android.app.Dialog;
> import android.app.ProgressDialog;
> import android.content.DialogInterface;
> import android.content.DialogInterface.OnClickListener;
> import android.content.Intent;
> import android.content.SharedPreferences;
> import android.widget.*;
> import android.net.http.AndroidHttpClient;
> import android.os.Bundle;
> import android.util.Log;
> import android.view.*;
>
> import java.io.BufferedReader;
> import java.io.IOException;
> import java.io.InputStream;
> import java.io.InputStreamReader;
> import java.net.HttpURLConnection;
> import java.net.URI;
> import javax.xml.parsers.SAXParser;
> import javax.xml.parsers.SAXParserFactory;
>
> import org.apache.http.HttpEntity;
> import org.apache.http.HttpResponse;
> import org.apache.http.NameValuePair;
> import org.apache.http.client.HttpClient;
> import org.apache.http.client.entity.UrlEncodedFormEntity;
> import org.apache.http.client.methods.HttpGet;
> import org.apache.http.client.methods.HttpPost;
> import org.apache.http.impl.client.DefaultHttpClient;
> import org.apache.http.message.BasicNameValuePair;
> import org.apache.http.protocol.HTTP;
> import org.xml.sax.InputSource;
> import org.xml.sax.XMLReader;
> import org.ksoap2.SoapEnvelope;
> import org.ksoap2.serialization.SoapObject;
> import org.ksoap2.serialization.SoapSerializationEnvelope;
> import org.ksoap2.transport.HttpTransport;
> import org.ksoap2.*;
> import java.util.Hashtable;
> import org.ksoap2.serialization.KvmSerializable;
> import org.ksoap2.serialization.PropertyInfo;
>
> public class FindMyAndroidActivity extends Activity
> {
> private static final String SOAP_ACTION = "http://MyServer.com/
> HelloWorld";
> private static final String METHOD_NAME = "HelloWorld";
> private static final String NAMESPACE = "http://MyServer.com/";;
> //private static final String URL = "http://MyServer.com/
> MyWebService.asmx";
> private static final String URL = "http://MyServer.com/
> MyWebService.asmx";
>
> @Override
> protected void onCreate(Bundle savedInstanceState)
> {
> // TODO Auto-generated method stub
> super.onCreate(savedInstanceState);
> setContentView(R.layout.findMyAndroid);
> }
>
> public void FindMyAndroids(View view)
> {
> QueryMyAndroids();
> }
>
> public void CancelMyAndroid(View view)
> {
> Intent intent = new
> Intent(FindMyAndroidActivity.this,MyAndroidPickActivity.class);
> startActivity(intent);
> }
>
> public void QueryMyAndroids()
> {
> TextView tv = (TextView)findViewById(R.id.ListView01);
> AlertDialog.Builder aMessage;
> try
> {
> java.net.URL url = new java.net.URL(URL);
> java.net.URLConnection conn = url.openConnection();
> conn.setConnectTimeout(0);
> java.net.HttpURLConnection httpConnection =
> (HttpURLConnection)conn;
> httpConnection.connect();
> InputStream in = httpConnection.getInputStream();
> int responseCode = httpConnection.getResponseCode();
> if (responseCode == HttpURLConnection.HTTP_OK)
> {
> tv.setText(in.toString());
> }
>
> }
> catch (Exception aE)
> {
> tv.setText(aE.toString());
> }
> }
>
> }
>
> Error Message that I am receiving:
> org.apache.harmony.luni.internal.net.www.protocol.http.HttpURLConnectionImpl
> $LimitedInputStream@45f8d630
>
> Please help! :-|
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